Day 76 — FULL MOCK: Meta
Coding problem
| Problem | FULL MOCK: Meta |
| LeetCode ID(s) | — |
| Difficulty | Mixed |
| Pattern | Mock |
| Company tags | Meta |
| Suggested time | 40m |
Solution outline (coding)
- Follow the mock packet: read constraints, state brute force, then optimize.
- For each problem: 5 min plan, 20 min code, 5 min tests and complexity.
- Log misses: communication, edge cases, or slow pattern recognition.
Time complexity: Varies — mock setting.
Space complexity: Varies.
Show Python solution
class ReviewDay:
"""Practice / review: FULL MOCK: Meta."""
def practice_plan(self):
return [
"Pick 2–3 problems from this phase; re-solve timed without notes.",
"For each: pattern name, time/space complexity, one alternative approach.",
]
# Input: (your choice of problems from this week or phase)
# Output: a short list of gaps to drill before the next sessionSQL interview practice
1. Interview question
Companies / track: Meta
Meta: expect event logging, ads / integrity, and social product analytics—deduping, sessionization, and window functions are frequent themes.
What you are asked to write (SQL prompt):
Frame this as metrics work for **Meta**-scale surfaces (ads, product, or engagement — as the tables suggest).
Design a Meta-style mock in BigQuery: one product-analytics query and one reliability query (e.g., error spike detection), emphasizing readability and explainability.
Tables implied by the prompt:
query(e.g., error spike detection)
Engine: BigQuery — use its date, array, and approximate functions as documented.
2. Solution outline
- Clarify out loud: result grain (one row per what?), join keys, time zone, and any
ORDER BY/LIMIT/ tie-breakers. - Map Mock to SQL: say the relational equivalent (e.g. hash map →
GROUP BY+ key; two pointers → ordered window + filter). - Structure: CTEs (
WITH) — one step per CTE; validate on a tiny slice (counts, nulls, duplicates).
Show SQL solution (BigQuery)
Main query
SELECT DATE(ts) AS d, COUNT(*) AS events, COUNTIF(error) / COUNT(*) AS error_rate
FROM product_events
GROUP BY d;